Solution Manual of Principles of Electronic Materials and Devices 2nd Edition by S. O. Kasap

 

Solutions Manual to accompany Principles of Electronic Materials and Devices Second Edition S.O. Kasap University of Saskatchewan Boston Burr Ridge, IL Dubuque, IA Madison, WI New York San Francisco St. Louis Bangkok Bogotб Caracas Kuala Lumpur Lisbon London Madrid Mexico City Milan Montreal New Delhi Santiago Seoul Singapore Sydney Taipei Toronto.
Solutions to Principles of Electronic Materials and Devices: 2nd Edition (Summer 2001) Chapter 1 1.1 Second Edition ( 2001 McGraw-Hill) Chapter 1 1.1 The covalent bond Consider the H2 molecule in a simple way as two touching H atoms as depicted in Figure 1Q1-1. Does this arrangement have a lower energy than two separated H atoms? Suppose that electrons totally correlate their motions so that they move to avoid each other as in the snapshot in Figure 1Q1-1. The radius ro of the hydrogen atom is 0.0529 nm. The electrostatic potential energy PE of two charges Q1 and Q2 separated by a distance r is given by Q1Q2/(4πεor). Using the Virial Theorem stated in Example 1.1 (in textbook) consider the following: a. Calculate the total electrostatic potential energy (PE) of all the charges when they are arranged as shown in Figure 1Q1-1. In evaluating the PE of the whole collection of charges you must consider all pairs of charges and, at the same time, avoid double counting of interactions between the same pair of charges. The total PE is the sum of the following: electron 1 interacting with the proton at a distance ro on the left, proton at ro on the right, and electron 2 at a distance 2ro + electron 2 interacting with a proton at ro and another proton at 3ro + two protons, separated by 2ro, interacting with each other. Is this configuration energetically favorable? b. Given that in the isolated H-atom the PE is 2 × (–13.6 eV), calculate the change in PE with respect to two isolated H-atoms. Using the Virial theorem, find the change in the total energy and hence the covalent bond energy. How does this compare with the experimental value of 4.51 eV? Solution Nucleus Hydrogen ro e–Nucleus Hydrogen ro e– 2 1 Figure 1Q1-1 A simplified view of the covalent bond in H2 : a snap shot at one instant in time. The electrons correlate their motions and avoid each other as much as possible. a Consider the PE of the whole arrangement of charges shown in the figure. In evaluating the PE of all the charges, we must avoid double counting of interactions between the same pair of charges. The total PE is the sum of the following: Electron 1 interacting with the proton at a distance ro on the left, with the proton at ro on the right and with electron 2 at a distance 2ro + Electron 2 on the far left interacting with a proton at ro and another proton at 3ro + Two protons, separated by 2ro, interacting with each other

 

• Twitter
• Facebook
• Google
• Tumblr
• Pinterest